(x^2-2/x)-5=(2x-2/x)

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Solution for (x^2-2/x)-5=(2x-2/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^2-(2/x)-5 = 2*x-(2/x) // - 2*x-(2/x)

x^2-(2*x)-(2/x)+2/x-5 = 0

x^2-2*x-2*x^-1+2/x-5 = 0

x^2-2*x-5 = 0

DELTA = (-2)^2-(-5*1*4)

DELTA = 24

DELTA > 0

x = (24^(1/2)+2)/(1*2) or x = (2-24^(1/2))/(1*2)

x = (2*6^(1/2)+2)/2 or x = (2-2*6^(1/2))/2

x in { (2-2*6^(1/2))/2, (2*6^(1/2)+2)/2 }

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